9. 22.Time is money

   st="00:00:00"
   et="00:00:10"
   
   print abs(int(st.split(':')[0])*3600 + int(st.split(':')[1])*60 + int(st.split(':')[2])-(int(et.split(':')[0])*3600 + int(et.split(':')[1])*60 + int(et.split(':')[2])))
   

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10. 21.Back to the text string

    a="xabcbai"
    n=5
    print('YES' if [i for i in range(len(a)-n+1) if a[i:(i+n)] == a[i:(i+n)][::-1]] else 'NO')
    

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11. 20.Information encryption

    a="cagy"
    b=33
    
    print(''.join([chr((ord(i)-ord('a')+b)%26+ord('a')) for i in a]))
    

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12. 19.Single song

    a="abciLOVEjce"
    
    UPPER = a.upper()
    
    if 'LOVE' in UPPER:
        print 'LOVE'
    else:
        print 'SINGLE'
    

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13. 18.The inverse solution of greatest common divisor and least common multiple

    # x/a=m,y/a=n
    # b/x=n,b/y=m
    # m*n=b/a
    # therefore, x*y==a*b
    
    a=1200
    b=120
    
    if a<b:
        a,b=b,a
    
    newx=b
    newy=a
    # x is divisor of a and multiple of b
    for x in range(b ...

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14. 17.The number of common divisor

    a=24
    b=60
    if a<b:
        smaller=a
    else:
        smaller=b
    
    count=0
    for i in range(1,smaller+1):
        if a%i==0 and b%i==0:
            count+=1
    
    print count
    

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15. 16.Print the RMB amount

    #coding:utf-8
    
    # method 1
    a=-20700450
    bigFormat={0:u'零',1:u"壹",2:u"贰",3:u'叁',4:u'肆',5:u'伍',6:u'陆',7:u'柒',8:u'捌',9:u'玖'}
    unit =['',u'拾',u'佰',u'仟',u'万']
    
    rmb=""
    if a!=abs ...

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16. 14.Zen of Python

    import this
    print this.s
    

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17. 13.Bachelor of sadness

    a=4
    n=0
    while a!=0:
        if a%2!=0:
            n+=1
        a=a//2
    print n
    

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18. 12.The parity of the non zero at the end

    def count(num,i):
        if num==0:
            return 0
        if num%i==0:
            return 1+count(num/i,i)
        else:
            return 0
    
    def countodd(list):
        count2=0
        count5=0
        for i in range(len(list)):
            count2 += count(list[i], 2)
            count5 += count(list[i], 5)
    
        if count2>count5:
            return 0 ...

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